x-((x^2-7)/(2x))=x/2+7/(2x)

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Solution for x-((x^2-7)/(2x))=x/2+7/(2x) equation: 


D( x )

2*x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

x-((x^2-7)/(2*x)) = x/2+7/(2*x) // - x/2+7/(2*x)

x-((x^2-7)/(2*x))-(x/2)-(7/(2*x)) = 0

x-((x^2-7)/(2*x))-(x/2)+(-7/2)*x^-1 = 0

(-1*(x^2-7))/(2*x)+x-x/2-7/(2*x) = 0

(-1*2*(x^2-7))/(2*2*x)+(2*2*x*x)/(2*2*x)+(2*(-x)*x)/(2*2*x)+(-7*2)/(2*2*x) = 0

2*2*x*x-1*2*(x^2-7)+2*(-x)*x-7*2 = 0

2*x^2-2*x^2-14+14 = 0

14-14 = 0

0 = 0

0/(2*2*x) = 0

0/(2*2*x) = 0 // * 2*2*x

0 = 0

x belongs to the empty set

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